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[1373719012] Transcending infinity

No.56077 View ViewReplyOriginalReport
The limit of 1/n is commonly held to be infinity as n approaches zero.
However 1/0 is larger than infinity since infinity*0=0 and thats not x*0=1
At any point of n above zero you can regain the 1 by 1/n=x x*n=1
But zero is a special case,since no infinite number can regain 1(on the other hand 0/0 is obviously 1, since x/x=1. But its somehow "undefined".).
Clearly 1/0 is infinitely larger than any infinity and is inexpressible in terms of infinities. Lets define its as function.
F1(x) for F1(1) gives (1/0) but for F1(2) gives (1/0)/0 which is much larger.
Now imagine F2(1)=F1(1/0) and F3(1)=F2(1/0)
After that imagine Fn(1)=F(n-1)(1/0) with n=1/0 as Fz1(1)=Fn(1/0)
Applying the same process to Fz1(1/0) as F1/F2 we get Fz2(1) and finally Fzn(1)
Now imagine for a moment you can abstractize the transitions from Fn to Fzn
as a process with C(1) steps. Imagine C(1/0) steps and than.. C(Fzn(1)) steps
and if you persist applying the method recursively(which i spare from this text) you can end up in madhouse blabbering about things mortal man were not meant to know.